I have the following python code: I wanted to put a try/except on the requestAPI function so it does'nt break the code. I thought about this: I could do something like: But i think there's a better way of doing this. Answer You can achieve it without a try-except via dict.get(): This will return the value for key key if

Python pass array into function and use it in json return

I have the following python code:

import requests

def requestAPI(url):
  return requests.get(url=url).json()

UselessFact = RequestApi("https://uselessfacts.jsph.pl/random.json?language=en")['text']

I wanted to put a try/except on the requestAPI function so it does’nt break the code. I thought about this:

import requests

def requestAPI(url, keys):
  return requests.get(url=url).json() #Here is the struggle with passing the "keys" parameter into the return

UselessFact = RequestApi("https://uselessfacts.jsph.pl/random.json?language=en", ['text'])

I could do something like:

import requests

def requestAPI(url):
  try:
    return requests.get(url=url).json() 

  except:
    return False

UselessFact = RequestApi("https://uselessfacts.jsph.pl/random.json?language=en")['text'] if (condition here) else False

But i think there’s a better way of doing this.

Answer

You can achieve it without a try-except via dict.get():

def requestAPI(url, key):
    return requests.get(url=url).json().get(key, None)

This will return the value for key key if it exists in the JSON otherwise it will return None. If you want it to return False, do .get(key, False).

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Answer