Python: How to add specific character as transforming a list to a string in differentiating the last item in the list?

I want to transform a list to a string including the square brackets and comma and then concatenate with another string.

Input:
    list1 = [1, 4, 3, 2, 5]
    str1 = 'is a list.n'

Expected output:
    [1, 4, 3, 2, 5] is a list.

What I’m trying is like this:

path = [1, 4, 3, 2, 5]
str1 = 'is a list.n'
ss = '['
for item in path:
    ss += str(item) + ', '
ss += '] ' + str1
print(ss)

But this results in the following output:

[1, 4, 3, 2, 5, ] is a list.

How to prevent the last comma ‘,’ from generating as the process of transform?

I’m considering to take a specific process based on whether the item is the last one in the list.

But how can I know it?

Or else is there any other solution?

Really appreciate!

Answer

This is bad Approah:

path = [1, 4, 3, 2, 5]
str1 = 'is a list.n'
ss = '['
for i in range(len(Path)):
    if i != (len(path)-1):
        ss += str(path[i]) + ', '
    else:
        ss += str(path[i])
ss += '] ' + str1
print(ss)

A good Approach is using f-Strings.

print(f"{path} is a list.n")

if u doesn’t like f-strings then

print("{} is a list.n".format(path))