Product code looks like abcd2343, how to split by letters and numbers?

I have a list of product codes in a text file, on each line is the product code that looks like:

abcd2343 abw34324 abc3243-23A

So it is letters followed by numbers and other characters.

I want to split on the first occurrence of a number.

Answer

import re
s='abcd2343 abw34324 abc3243-23A'
re.split('(d+)',s)

> ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23', 'A']

Or, if you want to split on the first occurrence of a digit:

re.findall('d*D+',s)
> ['abcd', '2343 abw', '34324 abc', '3243-', '23A']

---

• d+ matches 1-or-more digits.
• d*D+ matches 0-or-more digits followed by 1-or-more non-digits.
• d+|D+ matches 1-or-more digits or 1-or-more non-digits.

Consult the docs for more about Python’s regex syntax.

---

re.split(pat, s) will split the string s using pat as the delimiter. If pat begins and ends with parentheses (so as to be a “capturing group”), then re.split will return the substrings matched by pat as well. For instance, compare:

re.split('d+', s)
> ['abcd', ' abw', ' abc', '-', 'A']   # <-- just the non-matching parts

re.split('(d+)', s)
> ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23', 'A']  # <-- both the non-matching parts and the captured groups

In contrast, re.findall(pat, s) returns only the parts of s that match pat:

re.findall('d+', s)
> ['2343', '34324', '3243', '23']

Thus, if s ends with a digit, you could avoid ending with an empty string by using re.findall('d+|D+', s) instead of re.split('(d+)', s):

s='abcd2343 abw34324 abc3243-23A 123'

re.split('(d+)', s)
> ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23', 'A ', '123', '']

re.findall('d+|D+', s)
> ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23', 'A ', '123']