Plot with variable limit of integration in python

I have function f(x) and I want to integrate the function from 0 to some point x in the interval (0,2). I know how to solve the problem in mathematica, however I don’t know how to solve this problem in python.

Mathematica

OM=0.3
OL=0.7
f[x_] := ((1 + x)^3 OM + OL)^(-1/2);
Plot[NIntegrate[f[x], {x, 0, z2}], {z2, 0, 2}]

JavaScript
​x
 
OM=0.3
OL=0.7
f[x_] := ((1 + x)^3 OM + OL)^(-1/2);
Plot[NIntegrate[f[x], {x, 0, z2}], {z2, 0, 2}]
​

My code in python:

import numpy as np
import matplotlib.pyplot as plt
from scipy import integrate

y = np.linspace(0, 2, 20)
Om=0.3
Ol=1-Om

def H(x):
    return (Om*(1+x)**3 +Ol)**(-1./2)

#Integral from a single point in the inverval
print quad(H,0,2)

JavaScript
 
import numpy as np
import matplotlib.pyplot as plt
from scipy import integrate
​
y = np.linspace(0, 2, 20)
Om=0.3
Ol=1-Om
​
def H(x):
    return (Om*(1+x)**3 +Ol)**(-1./2)
​
#Integral from a single point in the inverval
print quad(H,0,2)
​

How can I do exactly the same in python?

Answer

[integrate.quad(H, 0, t)[0] for t in y]

JavaScript
 
[integrate.quad(H, 0, t)[0] for t in y]
​

quads inputs are f, a, b, here you do integration from 0 to t for all t in y.

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Answer