Pandas multiple comparison on a single row

My source data looks like this:

data = { 'id': [1,2,3,4,5],
         '1_src1': ['a', 'b','c', 'd', 'e'] ,
       '1_src2': ['a', 'b','c', 'd', 'e'] ,
       '2_src1': ['a', 'b','f', 'd', 'e'] ,
       '2_src2': ['a', 'b','c', 'd', 'e'] ,
       '3_src1': ['a', 'b','c', 'd', 'e'] ,
       '3_src2': ['a', 'b','1', 'd', 'm'] }
pd.DataFrame(data)

I need to compare Second column with Third, Fourth Column with Fifth Column, Sixth with Seventh. Column names can change. So I have to consider the column positions and my first column with always has column name as id.

so if atleast one of comparisons (‘1_src1’ vs ‘1_src2’) ( ‘2_src1’ vs ‘2_src2’) fails if need to update 1 else 0. But if the comparison of (3_src1 vs 3_src2) fails if need to update 2 else 0.

My result should look like :

The code I tried :

I tried creating subset of columns like this. But I am unable to proceed how can I achieve this result.

cols_comp = []
for i in range(0,len(x),2):
    cols_comp.append(x[i:i+2])

Any help appreciated. Thanks.

@Edit: Adding one more condition: Right now, if my last comparison fails I am updating ‘res’ as 2 but how can I update ‘res’ as 2 if my last n comparison fails?

Answer

You can use:

import numpy as np

# compare columns by pair after 1st one
comp = df.iloc[:, 1::2].ne(df.iloc[:, 2::2].to_numpy())

# select rules
                     # True in last     # True in first 2 comp
df['res'] = np.select([comp.iloc[:, 2], comp.iloc[:, :2].any(1)],
                      [2, 1], # matching values
                      0) # default

output:

   id 1_src1 1_src2 2_src1 2_src2 3_src1 3_src2  res
0   1      a      a      a      a      a      a    0
1   2      b      b      b      b      b      b    0
2   3      c      c      f      c      c      1    2
3   4      d      d      b      d      d      d    1
4   5      e      e      e      e      e      m    2