Is it possible to use argparse
to capture an arbitrary set of optional arguments?
For example both the following should be accepted as inputs:
python script.py required_arg1 --var1 value1 --var2 value2 --var3 value3 python script.py required_arg1 --varA valueA --var2 value2 --varB valueB
a priori I don’t know what optional arguments would be specified receive but would handle them accordingly.
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Answer
This is kind of a hackish way, but it works well:
Check, which arguments are not added and add them
import argparse parser = argparse.ArgumentParser() parser.add_argument("foo") parser.add_argument("-bar", type=int) # parser can have any arguments, whatever you want! parsed, unknown = parser.parse_known_args() # this is an 'internal' method # which returns 'parsed', the same as what parse_args() would return # and 'unknown', the remainder of that # the difference to parse_args() is that it does not exit when it finds redundant arguments for arg in unknown: if arg.startswith(("-", "--")): # you can pass any arguments to add_argument parser.add_argument(arg.split('=')[0], type=<your type>, ...) args = parser.parse_args()
For example:
python3 arbitrary_parser.py ha -bar 12 -extra1 value1 -extra2 value2
Then the result would be
args = Namespace(bar=12, foo='ha', extra1='value1' extra2='value2')