This is what I have:
glob(os.path.join('src','*.c'))
but I want to search the subfolders of src. Something like this would work:
glob(os.path.join('src','*.c')) glob(os.path.join('src','*','*.c')) glob(os.path.join('src','*','*','*.c')) glob(os.path.join('src','*','*','*','*.c'))
But this is obviously limited and clunky.
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Answer
pathlib.Path.rglob
Use pathlib.Path.rglob
from the pathlib
module, which was introduced in Python 3.5.
from pathlib import Path for path in Path('src').rglob('*.c'): print(path.name)
If you don’t want to use pathlib, use can use glob.glob('**/*.c')
, but don’t forget to pass in the recursive
keyword parameter and it will use inordinate amount of time on large directories.
For cases where matching files beginning with a dot (.
); like files in the current directory or hidden files on Unix based system, use the os.walk
solution below.
os.walk
For older Python versions, use os.walk
to recursively walk a directory and fnmatch.filter
to match against a simple expression:
import fnmatch import os matches = [] for root, dirnames, filenames in os.walk('src'): for filename in fnmatch.filter(filenames, '*.c'): matches.append(os.path.join(root, filename))