This is the sequence:

1, 2, 3, -1, 7, -10, 3, -73, …

and actually it’s like this:

t(n) = (t(n-3) * t(n-2)) - t(n-1)

for example: `-10 = (3 * -1) - 7`

.

I used this code but it’s not acting like this equation that I have provided.

n1 = 1 n2 = 2 n3 = 3 m = eval(input("number: ")) if m < 4: if m == n1: print(n1) elif m == n2: print(n2) elif m == n3: print(n3) elif m >= 4: n4 = (n1 * n2 - n3) print(n4)

This is my solution to finding `t(m)`

n = [1,2,3] m = int(input("number: ")) #eval is a big security risk!!! while len(n) < m: n.append((n[-3] * n[-2] - n[-1])) print(n[m-1])

where n[negative number] is a number from the end of the list.

Results in:

1, 2, 3, -1, 7, -10, 3, -73, 43, -262, -2877, -8389, 762163, 23372990, etc.

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