How to reorder a python OrderedDict using cascading list values

I’ve seen simpler examples of this but I’m trying to get a bit more complex and can’t work it out.

If I have an OrderedDict in which the key describes a person and the value is a list of their [age, gender, hairColor].

from collections import OrderedDict
myOD = OrderedDict(adultMale1=[50, 'male', 'grey'], babyFemale=[1, 'female', 'red'], teenMale=[13, 'male', 'blonde'], teenFemale=[13, 'female', 'red'], adultMale2=[50, 'male', 'blonde'])
print myOD.keys()
# Result: myOD:  ['teenMale', 'babyFemale', 'adultMale2', 'teenFemale', 'adultMale1']

JavaScript
​x
 
from collections import OrderedDict
myOD = OrderedDict(adultMale1=[50, 'male', 'grey'], babyFemale=[1, 'female', 'red'], teenMale=[13, 'male', 'blonde'], teenFemale=[13, 'female', 'red'], adultMale2=[50, 'male', 'blonde'])
print myOD.keys()
# Result: myOD:  ['teenMale', 'babyFemale', 'adultMale2', 'teenFemale', 'adultMale1']
​
​

What I want is to sort the OrderedDict first by age, then by gender, and then by hairColor. This would then be the correct result I’m looking for.

# Result: ['babyFemale', 'teenFemale', 'teenMale', 'adultMale2', 'adultMale1']

JavaScript
 
# Result: ['babyFemale', 'teenFemale', 'teenMale', 'adultMale2', 'adultMale1']
​

I have figured out a way to sort by age.

sortAgeList = []
for v in myOD.values():
    sortAgeList.append(v[0])
sortAgeList.sort()

myNewOD = OrderedDict()
for age in sortAgeList:
    for key, value in myOD.items():
        if value[0] == age:
            myNewOD[key] = myOD[key]
print 'myNewOD: ', myNewOD.keys()  
# Result: myNewOD:  ['babyFemale', 'teenMale', 'teenFemale', 'adultMale2', 'adultMale1']

JavaScript
 
sortAgeList = []
for v in myOD.values():
    sortAgeList.append(v[0])
sortAgeList.sort()
​
myNewOD = OrderedDict()
for age in sortAgeList:
    for key, value in myOD.items():
        if value[0] == age:
            myNewOD[key] = myOD[key]
print 'myNewOD: ', myNewOD.keys()  
# Result: myNewOD:  ['babyFemale', 'teenMale', 'teenFemale', 'adultMale2', 'adultMale1']
​
​

However, I’ve tried multiple ways to extrapolate this approach to then re-sort any tie-breakers that are the same age and then again any tie-breakers that are the same gender, but it’s getting really complex and I keep thinking there must be a simpler way.

I’m hoping someone out there has an idea to help me out. Thank you all in advance.

Answer

The default sort order is already lexicographic.

>>> sorted(myOD, key=myOD.get)
['babyFemale', 'teenFemale', 'teenMale', 'adultMale2', 'adultMale1']

JavaScript
 
>>> sorted(myOD, key=myOD.get)
['babyFemale', 'teenFemale', 'teenMale', 'adultMale2', 'adultMale1']
​

Therefore:

>>> from operator import itemgetter
>>> OrderedDict(sorted(myOD.items(), key=itemgetter(1)))
OrderedDict([('babyFemale', [1, 'female', 'red']),
             ('teenFemale', [13, 'female', 'red']),
             ('teenMale', [13, 'male', 'blonde']),
             ('adultMale2', [50, 'male', 'blonde']),
             ('adultMale1', [50, 'male', 'grey'])])

JavaScript
 
>>> from operator import itemgetter
>>> OrderedDict(sorted(myOD.items(), key=itemgetter(1)))
OrderedDict([('babyFemale', [1, 'female', 'red']),
             ('teenFemale', [13, 'female', 'red']),
             ('teenMale', [13, 'male', 'blonde']),
             ('adultMale2', [50, 'male', 'blonde']),
             ('adultMale1', [50, 'male', 'grey'])])
​

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Answer