Aim to Achieve:
I want all objects where name attribute contains any word from the list.
I have:
list = ['word1','word2','word3'] ob_list = data.objects.filter( // What to write here ? ) // or any other way to get the objects where any word in list is contained, in // the na-me attribute of data.
For example:
if name="this is word2":
Then object with such a name should be returned since word2 is in the list.
Please help!
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Answer
You could use Q
objects to constuct a query like this:
from django.db.models import Q ob_list = data.objects.filter(reduce(lambda x, y: x | y, [Q(name__contains=word) for word in list]))
Edit:
reduce(lambda x, y: x | y, [Q(name__contains=word) for word in list]))
is a fancy way to write
Q(name__contains=list[0]) | Q(name__contains=list[1]) | ... | Q(name__contains=list[-1])
You could also use an explicit for loop to construct the Q
object.