How to pass empty string into integer in python?

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i have one file which is highcore.txt and it is empty.

i want if txt file is empty or if any number which is score is greater than any number in txt file , update the txt file , here is my code

def game():
   return 115

score = game()
with open("highscore.txt") as f:
   highScoreStr = f.read()
if int(highScoreStr)<score or highScoreStr=='':
   with open("highscore.txt","w") as f:
       f.write(str(score))

it is giving error

    if int(highScoreStr)<score or highScoreStr=='':
ValueError: invalid literal for int() with base 10: ''

how to fix this error

Answer

I don’t think it is possible to pass an empty string through int()

Since you know it starts as an empty string you’re probably better off writing 2 if statements:

if highScorStr == '':
    with open("highscore.txt","w") as f:
       f.write(str(score))
if int(highScoreStr)<score:
    with open("highscore.txt","w") as f:
       f.write(str(score))


Source: stackoverflow