I’m here with my code, here you can see it:
def generate_integer(level):
score = 0
i = 0
false = 0
level = int(level)
while i != 10:
# Choosing the numbers of digit if 1 >> 1-9 / if 2 >> 11-99 / if 3 >> 100-999
end = 10**level-1
# Define x and y
x = random.randint(0,end)
y = random.randint(0,end)
answer = x + y
# Users cal
user = int(input(f'{x} + {y} = '))
if user == answer:
score = score + 1
while user != answer:
false + 1
print('EEE')
user = int(input(f'{x} + {y} = '))
if false == 3:
print(f'{x} + {y} = {answer}')
i = i + 1
print(f'score: {score}/10')
Let me explain: I defined false for, if user inputs the answer 3 times and all of them for that question are false, show user the answer and continue asking
Actually this code asks 10 different math questions, this is a part of my code, I’m checking if answer is not true print(‘EEE’) and re ask it again, but if user tries 3 time and all incorrect, then I show the answer, pass that question and keep asking other questions.
If you have any ideas for re asking question, when users input was non-numerical, I’ll be thankful.
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Answer
def check(user_answer,correct_answer):
for a chance in range(2):
print("Wrong answer, try again")
user_answer=input('User please type your answer for the question')
if user_answer == correct_answer:
return 'True' # Given the Right answer
else:
print('Again wrong answer')
return 'False' #Given all wrongs answers
user_answer=input('User please type your answer for the question')
correct_answer=10
if user_answer != correct_answer:
result=check(user_answer,correct_answer)
if result:
print("your answer is correct")
else:
print("your all answers were wrong, the right answer is: ",correct_answer)
else:
print("Perfect your answer was right in the first guess")