When I handle an exception in python
try: a = dict() a[1] except Exception as e: print str(e)
It prints
1
I expect it to print
KeyError: 1
Is there a way to retrieve the default error message ?
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Answer
Instead of this:
print str(e)
do this:
print(type(e).__name__ + ": " + str(e))
or just this:
print(type(e).__name__, e)