I have a string as Julian date like "16152"
meaning 152’nd day of 2016 or "15234"
meaning 234’th day of 2015.
How can I convert these Julian dates to format like 20/05/2016
using Python 3 standard library?
I can get the year 2016 like this: date = 20 + julian[0:1]
, where julian
is the string containing the Julian date, but how can I calculate the rest according to 1th of January?
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Answer
The .strptime()
method supports the day of year format:
>>> import datetime >>> >>> datetime.datetime.strptime('16234', '%y%j').date() datetime.date(2016, 8, 21)
And then you can use strftime()
to reformat the date
>>> date = datetime.date(2016, 8, 21) >>> date.strftime('%d/%m/%Y') '21/08/2016'