I have a list in range (1 to 31).
The final list is l = [x, y, z]
You can see my code, it is work fine using three for loops:
l = range(1, 31) x = ([j for (i, j) in enumerate(l) if i % 10 == 0]) y = ([j for (i, j) in enumerate(l) if i % 10 == 4]) z = ([j for (i, j) in enumerate(l) if i % 10 == 9]) l1 = [x, y, z] print (l1) l = range(1, 31) x, y, z = ([j for (i, j) in enumerate(l) if i % 10 == 0]), ([j for (i, j) in enumerate(l) if i % 10 == 4]), ([j for (i, j) in enumerate(l) if i % 10 == 9]) l1 = [x, y, z] print (l1)
The outputs is:
[[1, 11, 21], [5, 15, 25], [10, 20, 30]] [[1, 11, 21], [5, 15, 25], [10, 20, 30]]
I tried to do it using only one for
loop.
l = ([(x,y,z) for (i1, x), (i2, y), (i3, z) in enumerate(l) if i1 % 10 == 0 and i2 % 10 == 4 and i3 % 10 == 9]) print l # l = ([(x,y,z) for ((i, x), (i, y), (i, z)) in enumerate(l) if i % 10 == 0 and i % 10 == 4 and i % 10 == 9]) # print l # l = ([(j1,j2,j3) for ((i1,i2,i3), (j1,j2,j3)) in enumerate(l) if i1 % 10 == 0 and i2 % 10 == 4 and i3 % 10 == 9]) # print l
I got this error:
l = ([(x,y,z) for (i1, x), (i2, y), (i3, z) in enumerate(l) if i1 % 10 == 0 and i2 % 10 == 4 and i3 % 10 == 9]) ValueError: need more than 2 values to unpack
I don’t know if I can do it or not.
please help me.
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Answer
Try –
l = range(1, 31) mylist = [] lst = [0, 4, 9] for i in lst: mylist.append([b for a, b in enumerate(l) if a % 10 == i]) print(mylist)
Or list comprehension –
mylist = [[b for a, b in enumerate(l) if a % 10 == i] for i in lst]