How to add the current query string to an URL in a Django template?

Question

When I load a page, there is a link "sameLink" that I want to append to it the query string of its containing page. I have following URL: How can I do that? Answer To capture the QUERY_PARAMS that were part of the request, you reference the dict that contains those parameters (request.GET) and urlencode them so they are acceptable

Accepted Answer

To capture the QUERY_PARAMS that were part of the request, you reference the dict that contains those parameters (request.GET) and urlencode them so they are acceptable as part of an href.  request.GET.urlencode returns a string that looks like ds=&date_published__year=2008 which you can put into a link on the page like so:<a href="sameLink/?{{ request.GET.urlencode }}">

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