I am trying to create a high score system for my game, but only want to display the top 5 high scores. I used a dictionary to store the scores and the names of the players. I want the program to remove the first score once there are more than 5 items. How do I remove items from a dictionary based on their order?
I tried to use .pop(index)
like so:
highscores = {"player1":"54", "player2":"56", "player3":"63", "player4":"72", "player5":"81", "player6":"94"} if len(highscores) > 5: highscores.pop(0)
However I get an error:
Traceback (most recent call last): File "c:Users-----DocumentsPython projectsPython NEA courseworktest.py", line 3, in <module> highscores.pop(0) KeyError: 0
Anyone know why this happens?
I found a solution:
highscores = {"player1":"54", "player2":"56", "player3":"63", "player4":"72", "player5":"81", "player6":"94"} thislist = [] for keys in highscores.items(): thislist += keys highscores.pop(thislist[0])
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Answer
What you can do is turn your dict into a list of tuples (the items), truncate that, then turn back into a dict. For example, to always keep only the last 5 values inserted:
highscores = dict(list(highscores.items())[-5:])
(Note that it is idempotent if there were fewer than 5 items to start with).