How do I find the directory of the running Python script from inside Python [3.3]? I have tried what was suggested at: How can I find script’s directory? , but I get “Invalid syntax” and directed to “os” (And I did import os).
The closest I have got to the answer is: sys.argv[0], but that still includes the file name, so I cannot use it. Is there any other way?
The part where it says rundir = sys.argv[0] is where the suggested code will go:
import os, sys
rundir = sys.argv[0]
print("Running from" + rundir)
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Answer
To get the directory that contains the module you are running:
import os path = os.path.dirname(os.path.realpath(__file__))
Or if you want the directory from which the script was invoked:
import os path = os.getcwd()
From the docs:
__file__is the pathname of the file from which the module was loaded, if it was loaded from a file.
Depending on how the script is called, this may be a relative path from os.getcwd(), so os.path.realpath(__file__) will convert this to an absolute path (or do nothing is the __file__ is already an absolute path). os.path.dirname() will then return the full directory by stripping off the filename.