How do I continue my try/catch in my while-loop

I’m making this blackjack game and I’m sure if you’ve played the game you know the rules. Basically I have 5 amount of chips and I’m letting the user type in their bets for the round. I have this try catch block thats supposed to not let the user type in anything below 0 and above the chip_amount. My exception for ValueError works fine and the while-loop continues if the user types “fff” or anything thats not a number. The program exits after if the user types in anything under 0 and above chip_amount, this is because the while-loop stops and I can’t put continue in my if test, how can I solve this in a good way?

print("n==== BLACKJACK GAME ====")

print(f'nYou have currently have {chip_amount} chips available.')

while True:
    try:
        chips_input = int(input("How many chips do you want to bet? "))
        if chips_input < 1:
            raise Exception("Sorry, you have to enter a number bigger than 1.")
        if chips_input > chip_amount:
            raise Exception(f'Sorry, you have to enter a number less than {chip_amount}.')
    except ValueError:
        print("nYou have to enter a number!")
        continue
    else:
        print(f'nYou bet {chips_input} chips out of your total of {chip_amount} chips.')

        print(f'nThe cards have been dealt. You have a {" and a ".join(player_hand)}, with a total value of {player_total}.')
        print(f'The dealers visible card is a {dealer_hand[0]}, with a value of {dealer_total_sliced}.')

Answer

Raise ValueErrors so that your except block will catch these too:

if chips_input < 1:
    raise ValueError("Sorry, you have to enter a number bigger than 1.")
if chips_input > chip_amount:
    raise ValueError(f'Sorry, you have to enter a number less than {chip_amount}.')

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Answer