I have a list of strings which looks like this: B = [' _ ', '|_', '|_/']
(if you put these strings on top of each other you get the character B).
So I have this list of strings but Visual Studio Code says that this string literal is not terminated…
I assume it means the second element in the list as it has a backslash. What can I do about it? I tried double backslash, but then it just prints double backslash if I print the line
Thanks in advance
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Answer
So i assume your code looks something like this:
def func(str): print("n".join(str)) A = [' _ ', '|_|', '| |'] B = [' _ ', '|_'', '|_/'] C = [' _ ', '| ', '|_ '] D = [' _ ', '| '', '|_/'] E = [' _ ', '|_ ', '|_ '] F = [' _ ', '|_ ', '| '] func(A) func(B) func(C) func(D) func(E) func(F)
This gives us this output:
_ |_' |_/
I assume the output you are looking for is more like this:
_ |_ |_/
You want that ‘ to be gone and replaced with , this doesnt mean the string is not terminated, it means that you escaped a quote. Lets take a look at the string that has this error, its the second string in the B array:
‘|_”
first it prints a | then it prints a _ and then it prints a ‘ (a quote which is escaped using a backslash)
We do not want to do this because we dont want to print a quote, but want to print a backslash character. this is done by escaping a backslash using a backslash (so you end up with a double backslash)
So the correct B array should be:
B = [' _ ', '|_\', '|_/']
You also appear to have made a similair mistake in D which should be D = [' _ ', '| '', '|_/']