How can I find the value of kt+1 for periods t=1…50?

I know that: k_t+1= (1−δ)k_t + s * k^θ_t s=0.08, δ=0.3, θ= 0.35, k₀=2.5

I wrote this:

(δ,s,θ) = (0.08,0.3,0.35)
k=2.5
K = (1-δ)*k+s*k**θ
print (K)

JavaScript
​x
 
(δ,s,θ) = (0.08,0.3,0.35)
k=2.5
K = (1-δ)*k+s*k**θ
print (K)
​

I want to calculate the value of k for periods 1,…,50 Of course, the result of my code is only for k₁. Can you help me understand how I can find the values up to k₅₀?

Answer

You can calculate it with a simple loop like this:

δ, s, θ = 0.08, 0.3, 0.35
k = [2.5]
for _ in range(50):
    k.append((1-δ)*k[-1]+s*k[-1]**θ)
print(k)

JavaScript
 
δ, s, θ = 0.08, 0.3, 0.35
k = [2.5]
for _ in range(50):
    k.append((1-δ)*k[-1]+s*k[-1]**θ)
print(k)
​

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Answer