Getting line number from the exception object

I have defined a custom Exception object and would like to get the line number of the exception.

class FlowException(Exception):
    pass

def something():
    print 2/3
    print 1/2
    print 2/0


try:
   something()
except Exception as e:
   raise FlowException("Process Exception", e)

Now, if there is a exception in something() it throws the FlowException but it does not give me the exact line number, How can I get the line number from FlowException(ie; it failed when it executed 2/0)?

Here is the output:–

raise FlowException("Process Exception", e)
__main__.FlowException: ('Process Exception', ZeroDivisionError('integer division or modulo by zero',))
[Finished in 0.4s with exit code 1]

Answer

The traceback object holds that info in the tb_lineno attribute:

import sys

# ...
except Exception as e:
   trace_back = sys.exc_info()[2]
   line = trace_back.tb_lineno
   raise FlowException("Process Exception in line {}".format(line), e)

Advertisement

Answer