Fixing code when printing frequent values, python

Related to Counter when 2 values are most frequent

I made a demo list for the example, Running it with “for i in range (len(lines))”:

from statistics import multimode
lines = [[0,1],[1,5],[1,3],[67,45],[98,23],[67,68],[23,2],[1,18],[23,67],[40,79],[40,234],[40,41],[41,51]]

most = multimode(item for sublist in lines for item in sublist)
for a in most:
    del_connected = [bin for bin in lines if a in bin] # these connected to the maximum occured 
    for i, k in del_connected:
        lines = [x for x in lines if k not in x]
        lines = [x for x in lines if i not in x]
print(lines)

First round, there is only one occurred value “1”, but in the second round there are 3: 41,23,67. That’s why I did a for loop and matched “most” to “a” but del_connected prints the wrong values and so the “lines” list itself –>

>>[[67, 45], [67, 68], [23, 67]]
>>[]
>>[[40, 79], [40, 234], [40, 41]]

How do I fix it’s print when there are more than one frequent value?

Answer

Do you want something like this:

lines = ...

while len(lines) > 0:
    print(lines)
    most = multimode(item for sublist in lines for item in sublist)
    connected = [
        bin
        for bin in lines
        for a in most
        if a in bin
    ]
    for i, k in connected:
        lines = [
            bin
            for bin in lines
            if (i not in bin) or (k not in bin)
        ]