Finding a ‘hello’ word in a different string, which it has ‘hello’ in it(additional)

Finding a ‘hello’ word in a different string, which it has ‘hello’ in it I should find a ‘hello’ word in a string, which I gave it from input too .I wrote this code by looking at the answer that someone gave to the below link’s question.

firststring = input() #ahhellllloou
to_find = "hello"

def check_string(firststring, to_find):
   c = 0
   for i in firststring:
       #print(i)
       if i == to_find[c]:
           c += 1
       if c == len(to_find):
           return "YES"
   return "NO"

print(check_string(firststring, to_find))

but I don’t want to use a def to solve the problem.

hello = "hello"
counter_hello = 0
bool_hello = False

for letter in string:
    if letter == hello[counter_hello]:
        counter_hello += 1
    if counter_hello == len(hello):
        bool_hello = True

if bool_hello == True:
    print("YES")
else:
    print("NO")

for hello string it works correct. also for pnnepelqomhhheollvlo. but when I give it ahhellllloou it doesn’t work. I can’t see where the bug is.

Answer

Your code is not the same. The return statement needs to be accounted for by breaking the loop

string = "ahhellllloou"
to_find = "hello"

match = False
c = 0
for i in string:
   if i == to_find[c]:
       c += 1
   if c == len(to_find):
       match = True
       break
print("YES" if match else "NO")

Note that a loop isn’t needed

>>> import re
>>> m = re.search('.*'.join('hello'), 'ahhellllloou')
>>> m is not None
True
>>> m = re.search('.*'.join('hello'), 'ahhellllliu')
>>> m is None
True