I need to extract the name of the parent directory of a certain path. This is what it looks like:
C:stuffdirectory_i_needsubdirfile.jpg
I would like to extract directory_i_need
.
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Answer
import os ## first file in current dir (with full path) file = os.path.join(os.getcwd(), os.listdir(os.getcwd())[0]) file os.path.dirname(file) ## directory of file os.path.dirname(os.path.dirname(file)) ## directory of directory of file ...
And you can continue doing this as many times as necessary…
Edit: from os.path, you can use either os.path.split or os.path.basename:
dir = os.path.dirname(os.path.dirname(file)) ## dir of dir of file ## once you're at the directory level you want, with the desired directory as the final path node: dirname1 = os.path.basename(dir) dirname2 = os.path.split(dir)[1] ## if you look at the documentation, this is exactly what os.path.basename does.