>>> os.path.basename("../dir/") '' $ basename ../dir/ dir
os.path.basename(path)
Return the base name of pathname path. This is the second element of the pair returned by passing path to the function
split()
. Note that the result of this function is different from the Unix basename program; where basename for'/foo/bar/'
returns'bar'
, thebasename()
function returns an empty string (''
).
Is there a function that isn’t different from Unix basename?
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Answer
Not in one function, AFAIK, but it is not difficult. Just remove the trailing slash first:
os.path.basename(os.path.normpath("../dir/"))