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Create celery tasks then run synchronously

My app gathers a bunch of phone numbers on a page. Once the user hits the submit button I create a celery task to call each number and give a reminder message then redirect them to a page where they can see the live updates about the call. I am using web sockets to live update the status of each call and need the tasks to execute synchronously as I only have access to dial out from one number.

So once the first call/task is completed, I want the next one to fire off.

I took a look at CELERY_ALWAYS_EAGER settings but it just went through the first iteration and stopped.

@task
def reminder(number):
    # CODE THAT CALLS NUMBER HERE....

def make_calls(request):
    for number in phone_numbers:                     
        reminder.delay(number)      

    return redirect('live_call_updates') 

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Answer

if you want to fire each call one after another, why dont you wrap all the calls in one task

@task
def make_a_lot_of_calls(numbers):
    for num in numbers:
        # Assuming that reminder blocks till the call finishes
        reminder(number)

def make_calls(request):
    make_a_lot_of_calls.delay(phone_numers)                          
    return redirect('live_call_updates') 
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