Converting elements list into single dictionary while scraping

I am scraping Glassdoor companies. There is a benefits section which will be different for every company, so I am grabbing all the elements in the div. That returns a list. Is there anyway to convert these into key:value pairs while scraping. They need to be written to a csv inside a loop.

dict1 = {"Company URL": company_url, "Over All Rating": over_all_rating, "Most Commented":final, "Benefits":benefits, "Benefits List":all_ben_list}
    with open('Glassdoor.csv', 'a+', encoding='utf-8-sig') as f:
        w = csv.DictWriter(f, dict1.keys())
        if not header_added:
            w.writeheader()

As of now, I am writing the list in 1 column like so.

                                       Benefits
['Health Care & Insurance (2747)', 'Life Insurance (2423)', 'Disability Insurance (674)', 'Dental..]

Ideally it should be like this.

Health Care & Insurance  Life Insurance    Disability Insurance..
      2747                  2423                 674
       

I have tried but cannot think of a way to do this because characters are returned one at a time, so cannot find a way to make the headline text key and the value of it as value and I cannot come up with a way to create a dict out of this. Any help is much appreciated.

Answer

you can use the string find method to find the brackets and extract the value to save it into a dictionary

Benefits=['Health Care & Insurance (2747)', 'Life Insurance (2423)', 'Disability Insurance (674)']
info_dict={}
for benift in Benefits:
    key= benift[:benift.find("(")]
    value = benift[benift.find("(")+1:benift.find(")")]
    info_dict[key]=int(value)

print(info_dict)

Output is :

{'Health Care & Insurance ': 2747, 'Life Insurance ': 2423, 'Disability Insurance ': 674}