Check for string in list items using list as reference

I want to replace items in a list based on another list as reference.

Take this example lists stored inside a dictionary:

dict1 = {
   "artist1": ["dance pop","pop","funky pop"],
   "artist2": ["chill house","electro house"],
   "artist3": ["dark techno","electro techno"]
}

Then, I have this list as reference:

wish_list = ["house","pop","techno"]

My result should look like this:

dict1 = {
   "artist1": ["pop"],
   "artist2": ["house"],
   "artist3": ["techno"]
}

I want to check if any of the list items inside “wishlist” is inside one of the values of the dict1. I tried around with regex, any.

This was an approach with just 1 list instead of a dictionary of multiple lists:

check = any(item in artist for item in wish_list)
    if check == True:
        artist_genres.clear() 
        artist_genres.append()

I am just beginning with Python on my own and am playing around with the SpotifyAPI to clean up my favorite songs into playlists. Thank you very much for your help!

Answer

A regex is not needed, you can get away by simply iterating over the list:

wish_list = ["house","pop","techno"]
dict1 = {
   "artist1": ["dance pop","pop","funky pop"],
   "artist2": ["chill house","electro house"],
   "artist3": ["dark techno","electro techno"]
}

dict1 = {
   # The key is reused as-is, no need to change it.
   # The new value is the wishlist, filtered based on its presence in the current value
   key: [genre for genre in wish_list if any(genre in item for item in value)]
   for key, value in dict1.items() # this method returns a tuple (key, value) for each entry in the dictionary
}

This implementation relies a lot on list comprehensions (and also dictionary comprehensions), you might want to check it if it’s new to you.