I’m stuck on this problem:
I was trying to return sum of list of numbers in the array ignoring sections of numbers starting with a 6 and extending to the next 9 (every 6 will be followed by at least one 9). Return 0 for no numbers.
Here are my test cases:
number_69([1, 3, 5]) --> 9 number_69([4, 5, 6, 7, 8, 9]) --> 24 number_69([2, 1, 6, 9, 11]) --> 14
I came up with something like:
def number_69(arr): for num in arr: if 6 not in arr and 9 not in arr: return sum(arr) return 0
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Answer
i guess we stop adding when we see 6 and we start again when we see 9
def number_69(arr): sum = 0 stop = False for num in arr: if num == 6: stop = True elif num == 9: stop = False elif stop is False: sum = sum + num return sum print(number_69([2, 1, 6, 9, 11]))