I need to find a way to get the image name of any given image from a url. For example, in “…/images/foo.png”, the image name is “foo.png”. Is there a way to read this url and save just the name of the image up until the “/”? Thanks!
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Answer
You can just use split
:
url = 'https://upload.wikimedia.org/wikipedia/en/d/d0/Dogecoin_Logo.png' *_, filename = url.split('/') print(filename) # Outputs Dogecoin_Logo.png