how to remove NaN from numpy subarray

I have following numpy array:

array([['0.0', '0.0'],
       ['3.0', '0.0'],
       ['3.5', '35000.0'],
       ['4.0', '70000.0'],
       ['4.2', 'nan'],
       ['4.5', '117000.0'],
       ['5.0', '165000.0'],
       ['5.2', 'nan'],
       ['5.5', '225000.0'],
       ['6.0', '285000.0'],
       ['6.2', 'nan'],
       ['6.5', '372000.0'],
       ['7.0', '459000.0'],
       ['7.5', '580000.0'],
       ['8.0', '701000.0'],
       ['8.1', 'nan'],
       ['8.5', '832000.0'],
       ['8.8', 'nan'],
       ['9.0', '964000.0'],
       ['9.5', '1127000.0'],
       ['33.0', 'nan'],
       ['35.0', 'nan']], dtype='<U12')

I want to drop all subarrays with nan values.

Desired output is:

array([['0.0', '0.0'],
       ['3.0', '0.0'],
       ['3.5', '35000.0'],
       ['4.0', '70000.0'],
       ['4.5', '117000.0'],
       ['5.0', '165000.0'],
       ['5.5', '225000.0'],
       ['6.0', '285000.0'],
       ['6.5', '372000.0'],
       ['7.0', '459000.0'],
       ['7.5', '580000.0'],
       ['8.0', '701000.0'],
       ['8.5', '832000.0'],
       ['9.0', '964000.0'],
       ['9.5', '1127000.0'], dtype='<U12')

I ended with trying with np.isnan(array) , but I got error ufunc 'isnan' not supported for the input types . One idea while writing this is to split array in two arrays and get nan indexes and apply filter on both arrays and merge back. Any help is appreciated.

Answer

First for some reason, the provided array is an array of strings. So before proceeding further we need to convert it to an array of floats:

# assuming your original array is arr
new_arr = arr.astype(float)

Then, we can filter the list elements, in a way to only keep the subarrays which second element is not NaN

filtered_list = np.array(list(filter(lambda x: not np.isnan(x[1]), new_arr)))