I want to check if number, based on lower and upper bound, has prime divisors only 3 and 5 and number should be multiplication of power of 3 and power of 5. My current solution is this. I want to optimize it, since checking powers with for loops isn’t good way in my opinion. Thanks in advance.
def checkNum(x):
for i in range(1,50):
for j in range(1,50):
return x == (3**i) * (5**j)
def printResult(l, r):
for i in range(l,r):
if checkNum(i):
print(i)
Based on comments I think this is the best way:
def checkNum(x):
while x%3==0:
x = x //3
while x%5==0:
x = x//5
return x==1
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Answer
I want to optimize it, since checking powers with for loops isn’t good way in my opinion.
Over a range of random numbers, we improve its speed by doing:
def checkNum0(x):
if x % 2 == 0: # eliminate half the numbers in one test!
return False
while x % 15 == 0: # speed up the process
x = x // 15
while x % 5 == 0:
x = x // 5
while x % 3 == 0:
x = x // 3
return x == 1
Or we can use a nested loop and combine both divisions into one:
def checkNum(x):
if x % 2 == 0: # eliminate half the numbers in one test!
return False
for divisor in (15, 5, 3):
while (quotient_remainder := divmod(x, divisor))[1] == 0:
x = quotient_remainder[0]
return x == 1