I have a DataFrame with 2-level index and column with the numerical values. I want to sort it by level-0 and level-1 index in such a way that the the order of 0-level index is determined by the sum of values from Value column (descending), and the order of 1-level index is also determined by the values in Value column. This is my code:
import pandas as pd df = pd.DataFrame() df["Index1"] = ["A", "A", "B", "B", "C", "C"] df["Index2"] = ["X", "Y", "X", "Y", "X", "Y"] df["Value"] = [1, 4, 7, 3, 2, 7] df = df.set_index(["Index1", "Index2"]) df
And this is the desired output (B is at the top because the sum is 10 and then we have X first because 7 >3):

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Answer
You can do this with pandas.DataFrame.sort_values :
out= (
df
.assign(temp_col = df.groupby(level=0).transform("sum"))
.sort_values(by=["temp_col", "Value"], ascending=[False, False])
.drop(columns="temp_col")
)
# Output :
print(out)
Value
Index1 Index2
B X 7
Y 3
C Y 7
X 2
A Y 4
X 1