Python count up by 5 after each iteration in for loop

I am trying to open a csv file in python and read the rows into a list.

The list is then sent to a function where I want to add 5 to the value of x after each iteration with the value of d going up by 10 after every 10th iteration.

d I have working but can’t quite figure out x. Please can someone help me understand where I am going wrong with my math. I thought setting x = 0 outside the loop and then x+=5 inside would do it.

results = []
with open('file.csv', newline='') as inputfile:
    for row in csv.reader(inputfile):
        results.append(row[0]) # 24 rows in csv file

def buildcount(listGroup, z):
    listGroup = listGroup
    z = z
    x = 0
    for i in range (0, len(listGroup))
        print(i)
        d = 10*(i // 10 + z)
        x +=5
        print(x) 
        if i % 10 == 0:
            x = 0
    return i

z = 10
mainInput = results
buildcount(mainInput)



#current output of x
5
5
10
15
20
25
30
35
40
45
5
10
15
20
25
30
35
40
45
5
10
15
20
25


#desired output of x
0
5
10
15
20
25
30
35
40
45
0
5
10
15
20
25
30
35
40
45
0
5
10
15

Answer

It looks like you’re looking for some fairly simple math on the loop counter:

def buildcount(listGroup):
    for i in range (0, len(listGroup)):
        x = (i % 10) * 5
        d = (i // 10) * 10
        print(f'i={i}, x={x}, d={d}')
    return i

Output (for a 24-entry listGroup):

i=0, x=0, d=0
i=1, x=5, d=0
i=2, x=10, d=0
i=3, x=15, d=0
i=4, x=20, d=0
i=5, x=25, d=0
i=6, x=30, d=0
i=7, x=35, d=0
i=8, x=40, d=0
i=9, x=45, d=0
i=10, x=0, d=10
i=11, x=5, d=10
i=12, x=10, d=10
i=13, x=15, d=10
i=14, x=20, d=10
i=15, x=25, d=10
i=16, x=30, d=10
i=17, x=35, d=10
i=18, x=40, d=10
i=19, x=45, d=10
i=20, x=0, d=20
i=21, x=5, d=20
i=22, x=10, d=20
i=23, x=15, d=20